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w(50-2w)=250
We move all terms to the left:
w(50-2w)-(250)=0
We add all the numbers together, and all the variables
w(-2w+50)-250=0
We multiply parentheses
-2w^2+50w-250=0
a = -2; b = 50; c = -250;
Δ = b2-4ac
Δ = 502-4·(-2)·(-250)
Δ = 500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{500}=\sqrt{100*5}=\sqrt{100}*\sqrt{5}=10\sqrt{5}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-10\sqrt{5}}{2*-2}=\frac{-50-10\sqrt{5}}{-4} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+10\sqrt{5}}{2*-2}=\frac{-50+10\sqrt{5}}{-4} $
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