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w(10w+1)=9
We move all terms to the left:
w(10w+1)-(9)=0
We multiply parentheses
10w^2+w-9=0
a = 10; b = 1; c = -9;
Δ = b2-4ac
Δ = 12-4·10·(-9)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-19}{2*10}=\frac{-20}{20} =-1 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+19}{2*10}=\frac{18}{20} =9/10 $
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