v2+11v+24=10

Solution for v2+11v+24=10 equation:

v2+11v+24=10

We move all terms to the left:

v2+11v+24-(10)=0

We add all the numbers together, and all the variables

v^2+11v+14=0

a = 1; b = 11; c = +14;
Δ = b2-4ac
Δ = 112-4·1·14
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{65}}{2*1}=\frac{-11-\sqrt{65}}{2}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{65}}{2*1}=\frac{-11+\sqrt{65}}{2}
$