v-9+10v+11=4(7v-7)+4(1-v)

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Solution for v-9+10v+11=4(7v-7)+4(1-v) equation: 



v-9+10v+11=4(7v-7)+4(1-v)

We move all terms to the left:

v-9+10v+11-(4(7v-7)+4(1-v))=0

We add all the numbers together, and all the variables

v+10v-(4(7v-7)+4(-1v+1))-9+11=0

We add all the numbers together, and all the variables

11v-(4(7v-7)+4(-1v+1))+2=0



We calculate terms in parentheses: -(4(7v-7)+4(-1v+1)), so:

4(7v-7)+4(-1v+1)

We multiply parentheses

28v-4v-28+4

We add all the numbers together, and all the variables

24v-24

Back to the equation:

-(24v-24)



We get rid of parentheses

11v-24v+24+2=0

We add all the numbers together, and all the variables

-13v+26=0

We move all terms containing v to the left, all other terms to the right

-13v=-26

v=-26/-13

v=+2

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