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v-8/2v=6
We move all terms to the left:
v-8/2v-(6)=0
Domain of the equation: 2v!=0We multiply all the terms by the denominator
v!=0/2
v!=0
v∈R
v*2v-6*2v-8=0
Wy multiply elements
2v^2-12v-8=0
a = 2; b = -12; c = -8;
Δ = b2-4ac
Δ = -122-4·2·(-8)
Δ = 208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{208}=\sqrt{16*13}=\sqrt{16}*\sqrt{13}=4\sqrt{13}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{13}}{2*2}=\frac{12-4\sqrt{13}}{4} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{13}}{2*2}=\frac{12+4\sqrt{13}}{4} $
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