v-10+1=9(1-3v)-2(v-6)

Solution for v-10+1=9(1-3v)-2(v-6) equation:

v-10+1=9(1-3v)-2(v-6)

We move all terms to the left:

v-10+1-(9(1-3v)-2(v-6))=0

We add all the numbers together, and all the variables

v-(9(-3v+1)-2(v-6))-10+1=0

We add all the numbers together, and all the variables

v-(9(-3v+1)-2(v-6))-9=0


We calculate terms in parentheses: -(9(-3v+1)-2(v-6)), so:

9(-3v+1)-2(v-6)

We multiply parentheses

-27v-2v+9+12

We add all the numbers together, and all the variables

-29v+21

Back to the equation:

-(-29v+21)


We get rid of parentheses

v+29v-21-9=0

We add all the numbers together, and all the variables

30v-30=0

We move all terms containing v to the left, all other terms to the right

30v=30

v=30/30

v=1