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v(5v-7)=0
We multiply parentheses
5v^2-7v=0
a = 5; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·5·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*5}=\frac{0}{10} =0 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*5}=\frac{14}{10} =1+2/5 $
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