u+1-2(-9u-2)=3(u-3)

Solution for u+1-2(-9u-2)=3(u-3) equation:

u+1-2(-9u-2)=3(u-3)

We move all terms to the left:

u+1-2(-9u-2)-(3(u-3))=0

We multiply parentheses

u+18u-(3(u-3))+4+1=0


We calculate terms in parentheses: -(3(u-3)), so:

3(u-3)

We multiply parentheses

3u-9

Back to the equation:

-(3u-9)


We add all the numbers together, and all the variables

19u-(3u-9)+5=0

We get rid of parentheses

19u-3u+9+5=0

We add all the numbers together, and all the variables

16u+14=0

We move all terms containing u to the left, all other terms to the right

16u=-14

u=-14/16

u=-7/8