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u(2u+9)=50
We move all terms to the left:
u(2u+9)-(50)=0
We multiply parentheses
2u^2+9u-50=0
a = 2; b = 9; c = -50;
Δ = b2-4ac
Δ = 92-4·2·(-50)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{481}}{2*2}=\frac{-9-\sqrt{481}}{4} $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{481}}{2*2}=\frac{-9+\sqrt{481}}{4} $
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