If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( b )
cos(39) = 0
b = 0
cos(39) = 0
cos(39) = 0
t_1 = cos(39)
cos(39) = 0
t_1 = 0
b należy do R
b in (-oo:+oo)
b = 0
b = 0
b belongs to the empty set
tan(39) = 27/b
b belongs to the empty set
| 39=27/b | | 16x^2-45=0 | | 4secx=3cosx | | 800/.80 | | 30-5y=3y+6 | | 7p-8p+p= | | x-.20x=75 | | x-.20x=800 | | x=5-x/3 | | 5=6-4/x | | 15-x/3=-x/5 | | 3x^2-180=12 | | 3X+13=-19-5 | | 3(7-1)= | | 13x^4y^3= | | 0y=X-2 | | 12x-32=6x+40 | | 2x+5=3x+18 | | 10x-9=12x+4 | | f(x)=ax+bx+c | | (2x-11)(3x+5)=0 | | 6x/9x-3/6x | | (x+-11)(x+-5)=0 | | (6x-11)(x-5)=0 | | x+3y+4z=-18 | | 6x-4=8(x+4) | | p^3-pq^2+p^2q-q^3= | | 5m+3n= | | x^2-6x+9-49y^2= | | 7x^5-7x^2y^3+6x^3y-6y^4= | | m^3+2m+1=0 | | 5h-2=18 |