If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
cos(22.5) = 0
x = 0
cos(22.5) = 0
cos(22.5) = 0
t_1 = cos(22.5)
cos(22.5) = 0
t_1 = 0
x należy do R
x in (-oo:+oo)
x = 0
x = 0
x belongs to the empty set
tan(22.5) = 5/x
x belongs to the empty set
| y^(9/7)y^(3/7) | | 3z-(-11)=29 | | 10(x-2)+10(2)=-x(10) | | 3z/(-22)=29 | | .53=ln(y) | | 3(5n+5)=-105 | | (2x^2)+3x+(3y^2)-y-15=0 | | X-7+3=10 | | 3z-(-11)=29whatisz | | 14=3y-5 | | 63-y=6y | | n^2+2*n-24=0 | | 58=4y-14 | | 7x-3=8z-1 | | -8-8k=80 | | 7g+18=60 | | 19p-17=10 | | y^(8/5)y^(6/5) | | Y+1-5=8 | | 0.4x-0.2x= | | 180+3x=x | | 6y-0.3=7y | | -5x^2-15x+30=0 | | 2(5n+5)=-105 | | -2(-3+4x)=-26 | | -16x^2+36x+50=y | | 15n+2(3n-2)= | | 7-(4n-7)=1-5n | | 8x-(5x-9)=33 | | 3(2)-6=-45 | | 4z-6=5z-2 | | 25x+15=24x-2 |