t=7.2t2-18

Solution for t=7.2t2-18 equation:

t=7.2t^2-18

We move all terms to the left:

t-(7.2t^2-18)=0

We get rid of parentheses

-7.2t^2+t+18=0

a = -7.2; b = 1; c = +18;
Δ = b2-4ac
Δ = 12-4·(-7.2)·18
Δ = 519.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{519.4}}{2*-7.2}=\frac{-1-\sqrt{519.4}}{-14.4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{519.4}}{2*-7.2}=\frac{-1+\sqrt{519.4}}{-14.4}
$