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t=16t^2+68t+60
We move all terms to the left:
t-(16t^2+68t+60)=0
We get rid of parentheses
-16t^2+t-68t-60=0
We add all the numbers together, and all the variables
-16t^2-67t-60=0
a = -16; b = -67; c = -60;
Δ = b2-4ac
Δ = -672-4·(-16)·(-60)
Δ = 649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-67)-\sqrt{649}}{2*-16}=\frac{67-\sqrt{649}}{-32} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-67)+\sqrt{649}}{2*-16}=\frac{67+\sqrt{649}}{-32} $
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