t/2t-(t+6t)=-2/7

Solution for t/2t-(t+6t)=-2/7 equation:

t/2t-(t+6t)=-2/7

We move all terms to the left:

t/2t-(t+6t)-(-2/7)=0


Domain of the equation: 2t!=0

t!=0/2

t!=0

t∈R


We add all the numbers together, and all the variables

t/2t-(+7t)-(-2/7)=0

We get rid of parentheses

t/2t-7t+2/7=0

We calculate fractions


-7t+7t/14t+4t/14t=0

We multiply all the terms by the denominator


-7t*14t+7t+4t=0

We add all the numbers together, and all the variables

11t-7t*14t=0

Wy multiply elements

-98t^2+11t=0

a = -98; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-98)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-98}=\frac{-22}{-196}
=11/98
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-98}=\frac{0}{-196}
=0
$