t/10=12

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Solution for t/10=12 equation: 


(cos(x/4))^2-x

(sin(x/4))^2-x

(-8*x)/(x^2+1)

2.91/3

(28.12*x)/156.98+(-8.52*y)/35.48+1;(-21.25*x)/156.98+(-9.88*y)/35.48+1

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