t-3(4-t)=3t-28

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Solution for t-3(4-t)=3t-28 equation: 



t-3(4-t)=3t-28

We move all terms to the left:

t-3(4-t)-(3t-28)=0

We add all the numbers together, and all the variables

t-3(-1t+4)-(3t-28)=0

We multiply parentheses

t+3t-(3t-28)-12=0

We get rid of parentheses

t+3t-3t+28-12=0

We add all the numbers together, and all the variables

t+16=0

We move all terms containing t to the left, all other terms to the right

t=-16

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