t+3(-2t-4)=3-4(2t+5)

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Solution for t+3(-2t-4)=3-4(2t+5) equation: 



t+3(-2t-4)=3-4(2t+5)

We move all terms to the left:

t+3(-2t-4)-(3-4(2t+5))=0

We multiply parentheses

t-6t-(3-4(2t+5))-12=0



We calculate terms in parentheses: -(3-4(2t+5)), so:

3-4(2t+5)

determiningTheFunctionDomain
-4(2t+5)+3

We multiply parentheses

-8t-20+3

We add all the numbers together, and all the variables

-8t-17

Back to the equation:

-(-8t-17)



We add all the numbers together, and all the variables

-5t-(-8t-17)-12=0

We get rid of parentheses

-5t+8t+17-12=0

We add all the numbers together, and all the variables

3t+5=0

We move all terms containing t to the left, all other terms to the right

3t=-5

t=-5/3

t=-1+2/3

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