t(t-2)-(t-1)(t-1)=t+1

Solution for t(t-2)-(t-1)(t-1)=t+1 equation:

t(t-2)-(t-1)(t-1)=t+1

We move all terms to the left:

t(t-2)-(t-1)(t-1)-(t+1)=0

We multiply parentheses

t^2-2t-(t-1)(t-1)-(t+1)=0

We get rid of parentheses

t^2-2t-(t-1)(t-1)-t-1=0

We multiply parentheses ..

t^2-(+t^2-1t-1t+1)-2t-t-1=0

We add all the numbers together, and all the variables

t^2-(+t^2-1t-1t+1)-3t-1=0

We get rid of parentheses

t^2-t^2+1t+1t-3t-1-1=0

We add all the numbers together, and all the variables

-1t-2=0

We move all terms containing t to the left, all other terms to the right

-t=2

t=2/-1

t=-2