t(t+4)-5t=t(6+t)-8

Solution for t(t+4)-5t=t(6+t)-8 equation:

t(t+4)-5t=t(6+t)-8

We move all terms to the left:

t(t+4)-5t-(t(6+t)-8)=0

We add all the numbers together, and all the variables

t(t+4)-5t-(t(t+6)-8)=0

We add all the numbers together, and all the variables

-5t+t(t+4)-(t(t+6)-8)=0

We multiply parentheses

t^2-5t+4t-(t(t+6)-8)=0


We calculate terms in parentheses: -(t(t+6)-8), so:

t(t+6)-8

We multiply parentheses

t^2+6t-8

Back to the equation:

-(t^2+6t-8)


We add all the numbers together, and all the variables

t^2-1t-(t^2+6t-8)=0

We get rid of parentheses

t^2-t^2-1t-6t+8=0

We add all the numbers together, and all the variables

-7t+8=0

We move all terms containing t to the left, all other terms to the right

-7t=-8

t=-8/-7

t=1+1/7