t(2t+4)=48

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Solution for t(2t+4)=48 equation:


Simplifying
t(2t + 4) = 48

Reorder the terms:
t(4 + 2t) = 48
(4 * t + 2t * t) = 48
(4t + 2t2) = 48

Solving
4t + 2t2 = 48

Solving for variable 't'.

Reorder the terms:
-48 + 4t + 2t2 = 48 + -48

Combine like terms: 48 + -48 = 0
-48 + 4t + 2t2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-24 + 2t + t2) = 0

Factor a trinomial.
2((-6 + -1t)(4 + -1t)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-6 + -1t)' equal to zero and attempt to solve: Simplifying -6 + -1t = 0 Solving -6 + -1t = 0 Move all terms containing t to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + -1t = 0 + 6 Combine like terms: -6 + 6 = 0 0 + -1t = 0 + 6 -1t = 0 + 6 Combine like terms: 0 + 6 = 6 -1t = 6 Divide each side by '-1'. t = -6 Simplifying t = -6

Subproblem 2

Set the factor '(4 + -1t)' equal to zero and attempt to solve: Simplifying 4 + -1t = 0 Solving 4 + -1t = 0 Move all terms containing t to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1t = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1t = 0 + -4 -1t = 0 + -4 Combine like terms: 0 + -4 = -4 -1t = -4 Divide each side by '-1'. t = 4 Simplifying t = 4

Solution

t = {-6, 4}

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