If it's not what You are looking for type in the equation solver your own equation and let us solve it.
((e^2*x)/2)*x
(5/4)/(3/5) = 0
cos((pi*x)/3)
X-((5*x^2)/3) = 0
b*((7*b-(6*y))/4)-(b*((3*b-(11*y))/4)) = 0
| 0.94+1=y-0.2 | | SA=pits+pir^2 | | 10(z+2)-4(z-3)=2(z-1)+3(z-3) | | t+30=3t | | X+4x=64 | | 3x-0.8=1.6 | | (5/4)/(3/5) | | h=-16t^2+1108 | | 2x^3+13x^2-48x=0 | | N=1/3ma | | 24=-3(21-y)+2(y-4) | | 30ab+5b= | | -7b+8=9-10b | | r=6(6m-7p) | | x-3+4=22 | | 2x/7-2=10 | | 6x+7-9x=-29 | | 3x-3=169 | | n-3+4.6=21.6 | | 5(4-4m)= | | -4(1+5n)= | | X-5x^2/3 | | 18(13c+19)= | | -3.5x=1x-24 | | -6(-7+8b)= | | 3(3v+3)= | | 128t^7+4=5 | | -3(1-6v)= | | -1+3-3x=-6x+15 | | 5x+6x+1=10x | | -7(n+7)= | | f(x)=7x^2+-26x-25 |