sqrt(3x+1)+sqrt(x-1)=2

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Solution for sqrt(3x+1)+sqrt(x-1)=2 equation: 


Simplifying
sqrt(3x + 1) + sqrt(x + -1) = 2

Reorder the terms:
qrst(1 + 3x) + sqrt(x + -1) = 2
(1 * qrst + 3x * qrst) + sqrt(x + -1) = 2
(1qrst + 3qrstx) + sqrt(x + -1) = 2

Reorder the terms:
1qrst + 3qrstx + qrst(-1 + x) = 2
1qrst + 3qrstx + (-1 * qrst + x * qrst) = 2
1qrst + 3qrstx + (-1qrst + qrstx) = 2

Reorder the terms:
1qrst + -1qrst + 3qrstx + qrstx = 2

Combine like terms: 1qrst + -1qrst = 0
0 + 3qrstx + qrstx = 2
3qrstx + qrstx = 2

Combine like terms: 3qrstx + qrstx = 4qrstx
4qrstx = 2

Solving
4qrstx = 2

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Divide each side by '4rstx'.
q = 0.5r-1s-1t-1x-1

Simplifying
q = 0.5r-1s-1t-1x-1

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