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x in (-oo:+oo)
x*(sin(5*x)/2) = 0
x = 0
sin(5*x)/2 = 0
sin(5*x)/2 = 0 // * 2
sin(5*x) = 0
sin(5*x) = 0 <=> 5*x = pi*k_1 i k_1 należy do I
t_1 = pi*k_1
5*x-t_1 = 0
5*x-t_1 = 0 // + t_1
5*x = t_1 // : 5
x = t_1/5
x = pi*k_1/5 i k_1 należy do I
x*(sin(5*x)/2) = 0 <=> x = 0 or x*(sin(5*x)/2) = 0 <=> sin(5*x)/2 = 0
x in { 0, pi*k_1/5 }
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