sin(5pi/x)

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Solution for sin(5pi/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

sin((5*pi)/x) = 0

sin((5*pi)/x) = 0  <=>  (5*pi)/x = pi*k_1 i k_1 należy do I

t_1 = pi*k_1

(5*pi)/x-t_1 = 0

5*pi*x^-1 = t_1 // : 5*pi

x^-1 = t_1/(5*pi)

-1 < 0

1/(x^1) = t_1/(5*pi) // * x^1

1 = (t_1/(5*pi))*x^1 // : t_1/(5*pi)

5*pi*t_1^-1 = x^1

x = 5*pi*t_1^-1

x = 5*pi*pi*k_1^-1 i k_1 należy do I

x = 5*pi*pi*k_1^-1

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