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t in (-oo:+oo)
sin((4*pi*t)/5) = 0
sin((4*pi*t)/5) = 0 <=> (4*pi*t)/5 = pi*k_1 i k_1 należy do I
t_1 = pi*k_1
(4*pi*t)/5-t_1 = 0
((4*pi)/5)*t-t_1 = 0 // + t_1
((4*pi)/5)*t = t_1 // : (4*pi)/5
t = t_1/((4*pi)/5)
t = pi*k_1/((4*pi)/5) i k_1 należy do I
t = pi*k_1/((4*pi)/5)
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