sin(2x-pi/4)=0

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Solution for sin(2x-pi/4)=0 equation: 


x in (-oo:+oo)

sin(2*x-(pi/4)) = 0

sin(2*x-(pi/4)) = 0  <=>  2*x-(pi/4) = pi*k_1 i k_1 należy do I

t_1 = pi*k_1

2*x-t_1-(pi/4) = 0

2*x-t_1-(pi/4) = 0 // + -t_1-(pi/4)

2*x = -(-t_1-(pi/4)) // : 2

x = (-(-t_1-(pi/4)))/2

x = (t_1+pi/4)/2

x = (pi*k_1+pi/4)/2 i k_1 należy do I

x = (pi*k_1+pi/4)/2

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