sin(10x)-cos(4x)+sin(2x)=0

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Solution for sin(10x)-cos(4x)+sin(2x)=0 equation:


Simplifying
sin(10x) + -1cos(4x) + sin(2x) = 0

Remove parenthesis around (10x)
ins * 10x + -1cos(4x) + sin(2x) = 0

Reorder the terms for easier multiplication:
10ins * x + -1cos(4x) + sin(2x) = 0

Multiply ins * x
10insx + -1cos(4x) + sin(2x) = 0

Remove parenthesis around (4x)
10insx + -1cos * 4x + sin(2x) = 0

Reorder the terms for easier multiplication:
10insx + -1 * 4cos * x + sin(2x) = 0

Multiply -1 * 4
10insx + -4cos * x + sin(2x) = 0

Multiply cos * x
10insx + -4cosx + sin(2x) = 0

Remove parenthesis around (2x)
10insx + -4cosx + ins * 2x = 0

Reorder the terms for easier multiplication:
10insx + -4cosx + 2ins * x = 0

Multiply ins * x
10insx + -4cosx + 2insx = 0

Reorder the terms:
-4cosx + 10insx + 2insx = 0

Combine like terms: 10insx + 2insx = 12insx
-4cosx + 12insx = 0

Solving
-4cosx + 12insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-12insx' to each side of the equation.
-4cosx + 12insx + -12insx = 0 + -12insx

Combine like terms: 12insx + -12insx = 0
-4cosx + 0 = 0 + -12insx
-4cosx = 0 + -12insx
Remove the zero:
-4cosx = -12insx

Divide each side by '-4osx'.
c = 3ino-1

Simplifying
c = 3ino-1

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