s=31/2s=54

Solution for s=31/2s=54 equation:

s=31/2s=54

We move all terms to the left:

s-(31/2s)=0


Domain of the equation: 2s)!=0

s!=0/1

s!=0

s∈R


We add all the numbers together, and all the variables

s-(+31/2s)=0

We get rid of parentheses

s-31/2s=0

We multiply all the terms by the denominator


s*2s-31=0

Wy multiply elements

2s^2-31=0

a = 2; b = 0; c = -31;
Δ = b2-4ac
Δ = 02-4·2·(-31)
Δ = 248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{248}=\sqrt{4*62}=\sqrt{4}*\sqrt{62}=2\sqrt{62}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{62}}{2*2}=\frac{0-2\sqrt{62}}{4}
=-\frac{2\sqrt{62}}{4}
=-\frac{\sqrt{62}}{2}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{62}}{2*2}=\frac{0+2\sqrt{62}}{4}
=\frac{2\sqrt{62}}{4}
=\frac{\sqrt{62}}{2}
$