s=3(3-2)/5(r+2)

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Solution for s=3(3-2)/5(r+2) equation: 


x in (-oo:+oo)

s = ((3*(3-2))/5)*(r+2) // - ((3*(3-2))/5)*(r+2)

s-(((3*(3-2))/5)*(r+2)) = 0

(-3/5)*(3-2)*(r+2)+s = 0

s-3/5*(r+2) = 0

s-3/5*(r+2) = 0

s-3/5*r-6/5 = 0

s-3/5*r-6/5 = 0

x belongs to the empty set

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