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s2=21s-22=0
We move all terms to the left:
s2-(21s-22)=0
We add all the numbers together, and all the variables
s^2-(21s-22)=0
We get rid of parentheses
s^2-21s+22=0
a = 1; b = -21; c = +22;
Δ = b2-4ac
Δ = -212-4·1·22
Δ = 353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{353}}{2*1}=\frac{21-\sqrt{353}}{2} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{353}}{2*1}=\frac{21+\sqrt{353}}{2} $
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