s+(s+1)+(s+2)=63

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Solution for s+(s+1)+(s+2)=63 equation:



s+(s+1)+(s+2)=63
We move all terms to the left:
s+(s+1)+(s+2)-(63)=0
We get rid of parentheses
s+s+s+1+2-63=0
We add all the numbers together, and all the variables
3s-60=0
We move all terms containing s to the left, all other terms to the right
3s=60
s=60/3
s=20

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