s+(2/s)=-3

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Solution for s+(2/s)=-3 equation: 


D( s )

s = 0

s = 0

s = 0

s in (-oo:0) U (0:+oo)

s+2/s = -3 // + 3

s+2/s+3 = 0

1*s^1+2*s^-1+3*s^0 = 0

(1*s^2+3*s^1+2*s^0)/(s^1) = 0 // * s^2

s^1*(1*s^2+3*s^1+2*s^0) = 0

s^1

s^2+3*s+2 = 0

s^2+3*s+2 = 0

DELTA = 3^2-(1*2*4)

DELTA = 1

DELTA > 0

s = (1^(1/2)-3)/(1*2) or s = (-1^(1/2)-3)/(1*2)

s = -1 or s = -2

s in { -2, -1} 

s in { -2, -1 }

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