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r=6/6r-6
We move all terms to the left:
r-(6/6r-6)=0
Domain of the equation: 6r-6)!=0We get rid of parentheses
r∈R
r-6/6r+6=0
We multiply all the terms by the denominator
r*6r+6*6r-6=0
Wy multiply elements
6r^2+36r-6=0
a = 6; b = 36; c = -6;
Δ = b2-4ac
Δ = 362-4·6·(-6)
Δ = 1440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1440}=\sqrt{144*10}=\sqrt{144}*\sqrt{10}=12\sqrt{10}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12\sqrt{10}}{2*6}=\frac{-36-12\sqrt{10}}{12} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12\sqrt{10}}{2*6}=\frac{-36+12\sqrt{10}}{12} $
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