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r-9=6/r-5=9
We move all terms to the left:
r-9-(6/r-5)=0
Domain of the equation: r-5)!=0We get rid of parentheses
r∈R
r-6/r+5-9=0
We multiply all the terms by the denominator
r*r+5*r-9*r-6=0
We add all the numbers together, and all the variables
-4r+r*r-6=0
Wy multiply elements
r^2-4r-6=0
a = 1; b = -4; c = -6;
Δ = b2-4ac
Δ = -42-4·1·(-6)
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{10}}{2*1}=\frac{4-2\sqrt{10}}{2} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{10}}{2*1}=\frac{4+2\sqrt{10}}{2} $
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