q=4(q-8)=7q+5

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Solution for q=4(q-8)=7q+5 equation: 



q=4(q-8)=7q+5

We move all terms to the left:

q-(4(q-8))=0



We calculate terms in parentheses: -(4(q-8)), so:

4(q-8)

We multiply parentheses

4q-32

Back to the equation:

-(4q-32)



We get rid of parentheses

q-4q+32=0

We add all the numbers together, and all the variables

-3q+32=0

We move all terms containing q to the left, all other terms to the right

-3q=-32

q=-32/-3

q=10+2/3

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