q+1/q+4q+3

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Solution for q+1/q+4q+3 equation: 


D( q )

q = 0

q = 0

q = 0

q in (-oo:0) U (0:+oo)

q+4*q+1/q+3 = 0

5*q^1+1*q^-1+3*q^0 = 0

(5*q^2+3*q^1+1*q^0)/(q^1) = 0 // * q^2

q^1*(5*q^2+3*q^1+1*q^0) = 0

q^1

5*q^2+3*q+1 = 0

5*q^2+3*q+1 = 0

DELTA = 3^2-(1*4*5)

DELTA = -11

DELTA < 0

q in { } 

q belongs to the empty set

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