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p=1/2p
We move all terms to the left:
p-(1/2p)=0
Domain of the equation: 2p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
p-(+1/2p)=0
We get rid of parentheses
p-1/2p=0
We multiply all the terms by the denominator
p*2p-1=0
Wy multiply elements
2p^2-1=0
a = 2; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·2·(-1)
Δ = 8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8}=\sqrt{4*2}=\sqrt{4}*\sqrt{2}=2\sqrt{2}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{2}}{2*2}=\frac{0-2\sqrt{2}}{4} =-\frac{2\sqrt{2}}{4} =-\frac{\sqrt{2}}{2} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{2}}{2*2}=\frac{0+2\sqrt{2}}{4} =\frac{2\sqrt{2}}{4} =\frac{\sqrt{2}}{2} $
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