p=(p/9)+1=3

Solution for p=(p/9)+1=3 equation:

p=(p/9)+1=3

We move all terms to the left:

p-((p/9)+1)=0

We add all the numbers together, and all the variables

p-((+p/9)+1)=0

We multiply all the terms by the denominator


p*9)+1)-((+p=0

We add all the numbers together, and all the variables

p+p*9)+1)-((=0

Wy multiply elements

9p^2+p=0

a = 9; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·9·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*9}=\frac{-2}{18}
=-1/9
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*9}=\frac{0}{18}
=0
$