p=(2p-1)/3

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Solution for p=(2p-1)/3 equation: 



p=(2p-1)/3

We move all terms to the left:

p-((2p-1)/3)=0

We multiply all the terms by the denominator


p*3)-((2p-1)=0

Wy multiply elements

3p^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{6}=0$

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