p2=726

Solution for p2=726 equation:

p2=726

We move all terms to the left:

p2-(726)=0

We add all the numbers together, and all the variables

p^2-726=0

a = 1; b = 0; c = -726;
Δ = b2-4ac
Δ = 02-4·1·(-726)
Δ = 2904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2904}=\sqrt{484*6}=\sqrt{484}*\sqrt{6}=22\sqrt{6}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22\sqrt{6}}{2*1}=\frac{0-22\sqrt{6}}{2}
=-\frac{22\sqrt{6}}{2}
=-11\sqrt{6}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22\sqrt{6}}{2*1}=\frac{0+22\sqrt{6}}{2}
=\frac{22\sqrt{6}}{2}
=11\sqrt{6}
$