p2=0.8

Solution for p2=0.8 equation:

p2=0.8

We move all terms to the left:

p2-(0.8)=0

We add all the numbers together, and all the variables

p^2-0.8=0

a = 1; b = 0; c = -0.8;
Δ = b2-4ac
Δ = 02-4·1·(-0.8)
Δ = 3.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3.2}}{2*1}=\frac{0-\sqrt{3.2}}{2}
=-\frac{\sqrt{}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3.2}}{2*1}=\frac{0+\sqrt{3.2}}{2}
=\frac{\sqrt{}}{2}
$