p2-14p=32

Solution for p2-14p=32 equation:

p2-14p=32

We move all terms to the left:

p2-14p-(32)=0

We add all the numbers together, and all the variables

p^2-14p-32=0

a = 1; b = -14; c = -32;
Δ = b2-4ac
Δ = -142-4·1·(-32)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-18}{2*1}=\frac{-4}{2}
=-2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+18}{2*1}=\frac{32}{2}
=16
$