p2+7p+33=8-3p

Solution for p2+7p+33=8-3p equation:

p2+7p+33=8-3p

We move all terms to the left:

p2+7p+33-(8-3p)=0

We add all the numbers together, and all the variables

p2+7p-(-3p+8)+33=0

We add all the numbers together, and all the variables

p^2+7p-(-3p+8)+33=0

We get rid of parentheses

p^2+7p+3p-8+33=0

We add all the numbers together, and all the variables

p^2+10p+25=0

a = 1; b = 10; c = +25;
Δ = b2-4ac
Δ = 102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{-10}{2}=-5$