p-13(p+4)=2(p+1)

Solution for p-13(p+4)=2(p+1) equation:

p-13(p+4)=2(p+1)

We move all terms to the left:

p-13(p+4)-(2(p+1))=0

We multiply parentheses

p-13p-(2(p+1))-52=0


We calculate terms in parentheses: -(2(p+1)), so:

2(p+1)

We multiply parentheses

2p+2

Back to the equation:

-(2p+2)


We add all the numbers together, and all the variables

-12p-(2p+2)-52=0

We get rid of parentheses

-12p-2p-2-52=0

We add all the numbers together, and all the variables

-14p-54=0

We move all terms containing p to the left, all other terms to the right

-14p=54

p=54/-14

p=-3+6/7