p(7p-4)=0

Solution for p(7p-4)=0 equation:

p(7p-4)=0

We multiply parentheses

7p^2-4p=0

a = 7; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·7·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*7}=\frac{0}{14}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*7}=\frac{8}{14}
=4/7
$