p(-25)=(-25)+5/10

Solution for p(-25)=(-25)+5/10 equation:

p(-25)=(-25)+5/10

We move all terms to the left:

p(-25)-((-25)+5/10)=0

We multiply parentheses

-25p-((-25)+5/10)=0

We multiply all the terms by the denominator


-25p*10)-((-25)+5=0

Wy multiply elements

-250p^2+5=0

a = -250; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-250)·5
Δ = 5000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5000}=\sqrt{2500*2}=\sqrt{2500}*\sqrt{2}=50\sqrt{2}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-50\sqrt{2}}{2*-250}=\frac{0-50\sqrt{2}}{-500}
=-\frac{50\sqrt{2}}{-500}
=-\frac{\sqrt{2}}{-10}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+50\sqrt{2}}{2*-250}=\frac{0+50\sqrt{2}}{-500}
=\frac{50\sqrt{2}}{-500}
=\frac{\sqrt{2}}{-10}
$