n=5+3(n-1)

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Solution for n=5+3(n-1) equation: 



n=5+3(n-1)

We move all terms to the left:

n-(5+3(n-1))=0



We calculate terms in parentheses: -(5+3(n-1)), so:

5+3(n-1)

determiningTheFunctionDomain
3(n-1)+5

We multiply parentheses

3n-3+5

We add all the numbers together, and all the variables

3n+2

Back to the equation:

-(3n+2)



We get rid of parentheses

n-3n-2=0

We add all the numbers together, and all the variables

-2n-2=0

We move all terms containing n to the left, all other terms to the right

-2n=2

n=2/-2

n=-1

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