n=5(5n+4)+(n-2)=

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Solution for n=5(5n+4)+(n-2)= equation: 



n=5(5n+4)+(n-2)=

We move all terms to the left:

n-(5(5n+4)+(n-2))=0



We calculate terms in parentheses: -(5(5n+4)+(n-2)), so:

5(5n+4)+(n-2)

We multiply parentheses

25n+(n-2)+20

We get rid of parentheses

25n+n-2+20

We add all the numbers together, and all the variables

26n+18

Back to the equation:

-(26n+18)



We get rid of parentheses

n-26n-18=0

We add all the numbers together, and all the variables

-25n-18=0

We move all terms containing n to the left, all other terms to the right

-25n=18

n=18/-25

n=-18/25

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