n=3n-(2-n)

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Solution for n=3n-(2-n) equation: 



n=3n-(2-n)

We move all terms to the left:

n-(3n-(2-n))=0

We add all the numbers together, and all the variables

n-(3n-(-1n+2))=0



We calculate terms in parentheses: -(3n-(-1n+2)), so:

3n-(-1n+2)

We get rid of parentheses

3n+1n-2

We add all the numbers together, and all the variables

4n-2

Back to the equation:

-(4n-2)



We get rid of parentheses

n-4n+2=0

We add all the numbers together, and all the variables

-3n+2=0

We move all terms containing n to the left, all other terms to the right

-3n=-2

n=-2/-3

n=2/3

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