n=(5n+4)/n

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Solution for n=(5n+4)/n equation:


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

n = (5*n+4)/n // - (5*n+4)/n

n-((5*n+4)/n) = 0

(-1*(5*n+4))/n+n = 0

(-1*(5*n+4))/n+(n^2)/n = 0

n^2-1*(5*n+4) = 0

n^2-5*n-4 = 0

n^2-5*n-4 = 0

n^2-5*n-4 = 0

DELTA = (-5)^2-(-4*1*4)

DELTA = 41

DELTA > 0

n = (41^(1/2)+5)/(1*2) or n = (5-41^(1/2))/(1*2)

n = (41^(1/2)+5)/2 or n = (5-41^(1/2))/2

(n-((5-41^(1/2))/2))*(n-((41^(1/2)+5)/2)) = 0

((n-((5-41^(1/2))/2))*(n-((41^(1/2)+5)/2)))/n = 0

((n-((5-41^(1/2))/2))*(n-((41^(1/2)+5)/2)))/n = 0 // * n

(n-((5-41^(1/2))/2))*(n-((41^(1/2)+5)/2)) = 0

( n-((41^(1/2)+5)/2) )

n-((41^(1/2)+5)/2) = 0 // + (41^(1/2)+5)/2

n = (41^(1/2)+5)/2

( n-((5-41^(1/2))/2) )

n-((5-41^(1/2))/2) = 0 // + (5-41^(1/2))/2

n = (5-41^(1/2))/2

n in { (41^(1/2)+5)/2, (5-41^(1/2))/2 }

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